Re: configuration failed.

>>>>>"Kaoru" == Kaoru Fukui <k_fukui(a)highway.ne.jp&gt; writes: >>>>> Kaoru> Gcc doesn't have -z option which is linker option as ld. Only on PPC. On other platforms (at least all other Linux available to the Debian XEmacs maintainer and Solaris) where ld supports -z, gcc does pass it through to ld, although this is not documented. Eg, a random test program I have lying around on Debian Linux x86: bash-2.05a$ gcc --help | fgrep -e -z # no documentation bash-2.05a$ gcc -z nocombreloc -o test-z test.c # but it works bash-2.05a$ ./test-z uc << 14 = 4177920. bash-2.05a$ Unfortunately, it's possible that even if gcc is available to use as the linker, the linker may get called directly. So using -Wl, or -Xlinker is risky too. :-(