Re: [21.5] call-process-region problem
>>>> In <b9yhe0yqf4i.fsf(a)jpl.org> Katsumi Yamaoka
wrote:
It is because call-process-region of that version uses
call-process which inserts the output of a process in the point.
And it deletes the region which is pointed to by markers, after
a process is finished. Markers function rightly. Therefore,
they will be erased if the output of a process is inserted
within limits which markers point to.
Oops! Using markers is needless if the points aren't changed
while processing. Here is a new patch:
--- code-process.el~ 2002-11-10 22:07:29 +0000
+++ code-process.el 2003-11-21 10:14:54 +0000
＠＠ -171,15 +171,13 ＠＠
;; in the same buffer, make sure we track the insertion, and don't get
;; any of it in the deleted region if insertion happens at either end
;; of the region.
- (let ((s (and deletep (copy-marker start t)))
- (e (and deletep (copy-marker end))))
- (let ((retval
- (apply #'call-process program (list (current-buffer) start end)
- buffer displayp args)))
- ;; If start and end were the same originally, s will be beyond e now
- (if (and deletep (> e s))
- (delete-region s e))
- retval)))
+ (if deletep
+ (goto-char end))
+ (prog1
+ (apply #'call-process program (list (current-buffer) start end)
+ buffer displayp args)
+ (if deletep
+ (delete-region start end))))
(defun start-process (name buffer program &rest program-args)
"Start a program in a subprocess. Return the process object for it.
Probably, another function should be made if Ben wanted to write
that code for the particular purpose.
--
Katsumi Yamaoka <yamaoka(a)jpl.org>